NYT Pips hints and answers, Saturday, August 1, 2026

Start with the cell that must be greater than 4 at row 1, column 4. It has the fewest ways to be satisfied.

That cell is a 5. Only 2 dominoes have a 5: 5–2, 6–5.

Place the 6–5 domino with the 6 at row 1, column 3 and the 5 at row 1, column 4.

Full solution (domino: first half → second half): 5–2: R2C2→R3C2; 0–3: R3C3→R3C4; 6–5: R1C3→R1C4; 0–6: R1C1→R1C2; 3–4: R3C5→R2C5.

Start with the cell that must be less than 2 at row 3, column 1. It has the fewest ways to be satisfied.

That cell is a 0. Only 2 dominoes have a 0: 0–0, 5–0.

Place the 5–0 domino with the 5 at row 3, column 2 and the 0 at row 3, column 1.

Full solution (domino: first half → second half): 5–3: R2C2→R2C1; 0–0: R3C4→R4C4; 1–2: R2C3→R2C4; 3–3: R1C1→R1C2; 3–4: R1C3→R1C4; 6–6: R3C3→R4C3; 5–0: R3C2→R3C1.

Start with the cell that must equal 3 at row 1, column 3. It has the fewest ways to be satisfied.

That cell is a 3. Only 5 dominoes have a 3: 3–5, 3–3, 3–0, 6–3, 3–4.

Place the 3–5 domino with the 3 at row 1, column 3 and the 5 at row 1, column 4.

Full solution (domino: first half → second half): 1–5: R5C6→R5C7; 0–0: R5C4→R5C5; 3–5: R1C3→R1C4; 2–1: R2C4→R2C3; 3–3: R5C1→R5C2; 6–2: R3C6→R2C6; 4–4: R3C7→R4C7; 3–0: R6C3→R6C4; 5–5: R6C5→R6C6; 0–2: R3C5→R3C4; 1–4: R2C2→R3C2; 6–3: R3C1→R4C1; 4–2: R1C5→R2C5; 1–0: R4C6→R4C5; 3–4: R6C2→R6C1.