NYT Pips hints and answers, Tuesday, September 1, 2026

Start with the cell that must equal 4 at row 1, column 3. It has the fewest ways to be satisfied.

That cell is a 4, and only one domino has a 4: the 6–4.

Place the 6–4 domino with the 6 at row 2, column 3 and the 4 at row 1, column 3.

Full solution (domino: first half → second half): 6–4: R2C3→R1C3; 2–5: R4C3→R3C3; 3–1: R6C2→R6C1; 2–3: R4C2→R5C2; 6–3: R6C4→R6C5; 0–1: R4C4→R5C4.

Start with the cell that must equal 2 at row 4, column 1. It has the fewest ways to be satisfied.

That cell is a 2. Only 4 dominoes have a 2: 5–2, 2–2, 2–6, 2–0.

Place the 2–6 domino with the 2 at row 4, column 1 and the 6 at row 4, column 2.

Full solution (domino: first half → second half): 5–2: R2C2→R3C2; 2–2: R5C3→R5C4; 0–5: R4C4→R4C5; 2–6: R4C1→R4C2; 1–1: R1C3→R2C3; 2–0: R3C3→R4C3; 3–4: R3C4→R2C4.

Start with the cell that must equal 4 at row 3, column 5. It has the fewest ways to be satisfied.

That cell is a 4. Only 4 dominoes have a 4: 4–0, 4–2, 4–4, 4–6.

Place the 4–0 domino with the 4 at row 3, column 5 and the 0 at row 3, column 6.

Full solution (domino: first half → second half): 4–0: R3C5→R3C6; 1–3: R2C3→R2C4; 4–2: R5C1→R5C2; 3–6: R2C5→R2C6; 0–0: R2C7→R3C7; 3–5: R5C5→R5C6; 4–4: R3C1→R4C1; 5–2: R1C5→R1C4; 1–1: R2C1→R2C2; 2–0: R5C7→R4C7; 5–1: R3C3→R3C2; 3–2: R5C3→R5C4; 4–6: R1C7→R1C6; 2–1: R1C3→R1C2.