NYT Pips hints and answers, Monday, September 14, 2026

Start with the cell that must be greater than 1 at row 1, column 4. It has the fewest ways to be satisfied.

That cell is a 2, and only one domino has a 2: the 6–2.

Place the 6–2 domino with the 6 at row 1, column 3 and the 2 at row 1, column 4.

Full solution (domino: first half → second half): 6–4: R1C2→R1C1; 4–5: R2C1→R3C1; 6–6: R2C2→R2C3; 6–1: R2C4→R3C4; 6–2: R1C3→R1C4.

Start with the cell that must equal 2 at row 4, column 1. It has the fewest ways to be satisfied.

That cell is a 2. Only 2 dominoes have a 2: 4–2, 2–1.

Place the 2–1 domino with the 2 at row 4, column 1 and the 1 at row 3, column 1.

Full solution (domino: first half → second half): 4–2: R4C3→R5C3; 0–0: R1C4→R2C4; 4–1: R4C2→R3C2; 3–6: R3C3→R3C4; 0–4: R2C3→R2C2; 2–1: R4C1→R3C1; 4–4: R5C2→R6C2.

Start with the cell that must equal 3 at row 1, column 3. It has the fewest ways to be satisfied.

That cell is a 3. Only 5 dominoes have a 3: 5–3, 3–1, 3–2, 3–4, 3–0.

Place the 3–2 domino with the 3 at row 1, column 3 and the 2 at row 2, column 3.

Full solution (domino: first half → second half): 5–3: R6C1→R5C1; 0–0: R1C4→R1C5; 3–1: R4C1→R3C1; 2–4: R3C3→R3C4; 0–5: R4C8→R3C8; 3–2: R1C3→R2C3; 4–1: R7C9→R6C9; 5–2: R5C3→R4C3; 4–0: R3C5→R2C5; 6–1: R7C7→R6C7; 3–4: R5C5→R4C5; 2–1: R3C7→R2C7; 6–4: R2C9→R3C9; 3–0: R6C8→R5C8; 4–5: R7C2→R7C1.