NYT Pips hints and answers, Wednesday, September 30, 2026

Start with the cell that must equal 1 at row 1, column 4. It has the fewest ways to be satisfied.

That cell is a 1. Only 2 dominoes have a 1: 1–3, 5–1.

Place the 1–3 domino with the 1 at row 1, column 4 and the 3 at row 1, column 5.

Full solution (domino: first half → second half): 6–0: R2C2→R2C3; 1–3: R1C4→R1C5; 5–4: R3C5→R3C4; 5–1: R2C5→R2C4; 6–6: R3C1→R3C2.

Start with the cell that must equal 2 at row 3, column 2. It has the fewest ways to be satisfied.

That cell is a 2. Only 4 dominoes have a 2: 2–5, 2–2, 2–3, 2–1.

Place the 2–3 domino with the 2 at row 3, column 2 and the 3 at row 3, column 1.

Full solution (domino: first half → second half): 1–4: R1C2→R2C2; 2–5: R3C3→R2C3; 2–2: R4C2→R4C3; 5–3: R1C1→R2C1; 6–4: R1C3→R1C4; 2–3: R3C2→R3C1; 2–1: R2C4→R2C5.

Start with the cell that must be less than 1 at row 4, column 2. It has the fewest ways to be satisfied.

That cell is a 0. Only 2 dominoes have a 0: 0–0, 4–0.

Place the 4–0 domino with the 4 at row 4, column 1 and the 0 at row 4, column 2.

Full solution (domino: first half → second half): 0–0: R1C5→R1C6; 4–1: R2C2→R2C3; 3–2: R6C4→R6C5; 2–6: R4C6→R3C6; 4–5: R6C1→R5C1; 4–0: R4C1→R4C2; 1–5: R3C3→R3C2; 2–4: R1C2→R1C1; 3–4: R1C4→R1C3; 4–6: R2C5→R2C6; 3–1: R6C2→R6C3; 2–2: R5C6→R6C6; 2–5: R5C5→R5C4; 4–4: R2C1→R3C1; 5–6: R4C5→R3C5.