NYT Pips hints and answers, Saturday, October 10, 2026

Start with the cell that must equal 1 at row 1, column 2. It has the fewest ways to be satisfied.

That cell is a 1, and only one domino has a 1: the 6–1.

Place the 6–1 domino with the 6 at row 2, column 2 and the 1 at row 1, column 2.

Full solution (domino: first half → second half): 4–4: R2C3→R3C3; 6–1: R2C2→R1C2; 0–2: R3C1→R2C1; 0–5: R3C2→R4C2; 6–5: R4C4→R4C3.

Start with the cell that must be less than 3 at row 3, column 2. It has the fewest ways to be satisfied.

That cell is a 2. Only 2 dominoes have a 2: 1–2, 5–2.

Place the 5–2 domino with the 5 at row 3, column 3 and the 2 at row 3, column 2.

Full solution (domino: first half → second half): 3–3: R2C1→R2C2; 1–4: R2C3→R1C3; 4–4: R4C3→R4C4; 6–4: R4C2→R4C1; 1–2: R2C4→R3C4; 5–2: R3C3→R3C2; 6–5: R1C2→R1C1.

Start with the cell that must equal 3 at row 1, column 2. It has the fewest ways to be satisfied.

That cell is a 3. Only 6 dominoes have a 3: 0–3, 1–3, 2–3, 3–4, 3–5, 3–6.

Place the 3–4 domino with the 3 at row 1, column 2 and the 4 at row 2, column 2.

Full solution (domino: first half → second half): 0–1: R3C2→R3C3; 0–2: R2C6→R3C6; 0–3: R1C4→R1C3; 0–4: R2C5→R1C5; 0–5: R5C3→R6C3; 1–2: R2C4→R2C3; 1–3: R3C4→R3C5; 1–4: R5C2→R6C2; 1–5: R6C4→R6C5; 2–3: R5C4→R4C4; 2–4: R3C1→R2C1; 2–5: R5C5→R5C6; 3–4: R1C2→R2C2; 3–5: R4C3→R4C2; 4–5: R5C1→R4C1; 3–6: R4C6→R4C5.