NYT Pips hints and answers, Sunday, August 2, 2026

Start with the cell that must be greater than 5 at row 3, column 4. It has the fewest ways to be satisfied.

That cell is a 6, and only one domino has a 6: the 6–3.

Place the 6–3 domino with the 6 at row 3, column 4 and the 3 at row 3, column 3.

Full solution (domino: first half → second half): 0–0: R2C2→R2C3; 1–1: R1C1→R1C2; 3–5: R3C2→R3C1; 6–3: R3C4→R3C3; 2–0: R1C4→R1C3.

Start with the cell that must equal 3 at row 2, column 5. It has the fewest ways to be satisfied.

That cell is a 3. Only 3 dominoes have a 3: 0–3, 3–4, 3–3.

Place the 0–3 domino with the 0 at row 1, column 5 and the 3 at row 2, column 5.

Full solution (domino: first half → second half): 0–3: R1C5→R2C5; 5–5: R3C1→R3C2; 3–4: R4C3→R3C3; 6–2: R2C3→R2C2; 4–4: R2C4→R3C4; 3–3: R3C5→R3C6; 0–4: R1C4→R1C3.

Start with the cell that must equal 3 at row 2, column 2. It has the fewest ways to be satisfied.

That cell is a 3. Only 5 dominoes have a 3: 3–3, 1–3, 2–3, 5–3, 6–3.

Place the 3–3 domino with the 3 at row 2, column 1 and the 3 at row 2, column 2.

Full solution (domino: first half → second half): 1–6: R1C5→R1C6; 2–0: R3C9→R3C8; 1–4: R6C2→R6C1; 3–3: R2C1→R2C2; 0–0: R1C4→R2C4; 2–5: R3C3→R2C3; 1–3: R5C9→R4C9; 5–0: R3C7→R4C7; 2–6: R4C3→R4C2; 1–1: R6C4→R6C5; 2–3: R3C4→R3C5; 4–6: R5C7→R5C6; 0–1: R6C8→R6C9; 5–3: R6C7→R6C6; 2–1: R5C3→R6C3; 6–3: R4C6→R3C6.