NYT Pips hints and answers, Saturday, August 8, 2026

Start with the cell that must be greater than 5 at row 4, column 1. It has the fewest ways to be satisfied.

That cell is a 6, and only one domino has a 6: the 6–2.

Place the 6–2 domino with the 6 at row 4, column 1 and the 2 at row 4, column 2.

Full solution (domino: first half → second half): 5–1: R3C4→R3C3; 4–3: R4C3→R4C4; 0–5: R2C2→R3C2; 6–2: R4C1→R4C2; 0–0: R1C1→R1C2.

Start with the cell that must be less than 2 at row 4, column 2. It has the fewest ways to be satisfied.

That cell is a 0. Only 2 dominoes have a 0: 0–0, 0–1.

Place the 0–0 domino with the 0 at row 4, column 2 and the 0 at row 4, column 3.

Full solution (domino: first half → second half): 0–0: R4C2→R4C3; 0–1: R3C1→R3C2; 1–3: R2C4→R1C4; 1–5: R2C2→R2C3; 2–2: R3C5→R3C6; 2–6: R4C5→R4C4; 6–6: R3C3→R3C4.

Start with the cell that must equal 3 at row 2, column 2. It has the fewest ways to be satisfied.

That cell is a 3. Only 3 dominoes have a 3: 2–3, 3–3, 3–4.

Place the 3–4 domino with the 3 at row 2, column 2 and the 4 at row 3, column 2.

Full solution (domino: first half → second half): 0–1: R8C7→R7C7; 0–2: R8C1→R8C2; 0–4: R1C4→R1C5; 0–6: R2C4→R3C4; 1–6: R7C4→R6C4; 2–2: R6C2→R7C2; 2–3: R6C7→R5C7; 2–4: R5C2→R4C2; 2–5: R7C3→R8C3; 2–6: R6C3→R5C3; 3–3: R8C4→R8C5; 3–4: R2C2→R3C2; 4–6: R4C4→R5C4; 5–5: R1C3→R2C3; 5–6: R1C2→R1C1; 6–6: R3C3→R4C3.